In earlier lessons, students learned to use the standard algorithm to solve multiplication problems in which a two-digit number was multiplied by a two-digit number. In those lessons, they learned to use place value concepts to regroup ones into tens when needed.
In this lesson, students extend what they learned in those lessons to learn to multiply a three-digit number by a two-digit number. They learn to regroup by making a ten in the hundreds place from ten tens.
In earlier lessons, students have learned to divide 3-digit numbers by 1-digit numbers using the standard algorithm. The process emphasized the fact that division is finding a missing factor, which is the inverse of multiplication.
In this lesson, students start to extend their knowledge of that process to learn to solve division problems with two-digit divisors using the standard algorithm.
This lesson also makes salient the inverse nature of division and multiplication by focusing on the division operation as finding a missing factor. To support this understanding, a multiplication table is present which allows students to estimate each digit in the quotient using the values in the table as trial digits.
Each problem has a 3-digit dividend, a two-digit divisor, and the quotient is a whole number.
In the prior lesson, students learn to solve division problems when the dividend has three digits and the divisor has two digits, using a multiplication table to determine trial digits in the quotient.
In this lesson, students extend that knowledge and learn to complete the same kind of division problems without the aid of a multiplication table to determine trial digits in the quotient.